Geometry: Let's Get Parallel

Let's Get Parallel

You were introduced to Euclid's Parallel Postulate. That postulate has raised more questions in the last 2,000 years than any other postulate. Euclid spent a lot of time pondering parallel lines. He was very uncomfortable with his 5th postulate, because he firmly believed that he could prove it from other postulates and theorems. In this section, you'll be dealing with pairs of lines cut by a transversal. Remember all of the angle relationships that were involved with lines and transversals. There are alternate interior and exterior angles, same-side interior and exterior angles, corresponding angles, and vertical angles. Feel free to review these topics if you need some refreshment.

When dealing with parallel lines, you can freely invoke Euclid's 5th postulate. It's important to keep in mind that many of these results only hold for Euclidean geometry. You'll have to wait until Whose Geometry Is It Anyway? to enter the bizarre world of non-Euclidean geometry.

In order to explore the relationships between angles formed when parallel lines are cut by a transversal, you need a place to start. It's time to add another postulate to your collection.

• Postulate 10.1: If two parallel lines are cut by a transversal, then the corresponding angles are congruent.

To get a feel for this theorem, take a look at Figure 10.3. If lines l and m are parallel, and line t is a transversal, then 1 and 2 are corresponding angles. According to Postulate 10.1, 1 ~= 2. We can use this postulate to solve “find the measure of the angle” puzzles.

• Example 2: In Figure 10.4, l m and m1 = 112º. Find m2, m4, m5, and m8.

• Solution: Use Postulate 10.1, and the theorem about vertical angles to solve this problem. Because 1 and 4 are vertical angles, you know that they are congruent. Right away you know that m4 = 112º. Because 4 and 8 are corresponding angles, by Postulate 10.1 you know that 4 and 8. Because m4 = 112º , m8 =112 º. Because 8 and 5 are vertical angles, you know that 5 ~= 8, so m5 112º. All that's left is to find m2. Because 1 and 2 are supplementry angles (together they form a straight angle), you know that m1 + m2 = 180º. Substituting in for m1, you see that m1 + 112º = 180º. So m2 = 68º. To summarize: m2 = 68º , m4 = 112º , 5 = 112º , and m8 = 112º.